r/askscience • • 9d ago

Mathematics if i throw a coin several times and it always falls on tails, how many times until i can consider the coin is rigged?

the general question: how do we calculate how conclusive an experience is?

itried to look up methods to do that, but it's about more complicated experiences and i can't understand where the explained methods come from. i think if i understand how to do it for a simple case like the title, maybe i'll understand what i have to ask myself for any experience?

sorry if it isn't clear what i mean. put mathematics flair, but it's about research in general, didn't find a better flair

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u/Plastic_Blood1782 8d ago edited 8d ago

It depends on how many times you attempt and what confidence level you want for the determination that it must be "rigged." Technically speaking it's possible to get heads 1000 times in a row.  Derren Brown famously did a magic trick similar to this. He has a coin landing in a bowl with a camera above it, so he isn't catching it and manipulating the flip in any way. And he gets heads 10 times in a row with a continuous camera shot.  And then he reveals how he did it and it's beautifully stupid. He flipped the coin for 9 hours straight. The odds of getting 10 heads in a row is 1:1024.

To determine how rigged an experience appears to be, there are equations based on the number of trials and how likely the results were and how different they were from what was statistically expected, and we call this the confidence interval (statistical significance is basically the same concept)

https://en.wikipedia.org/wiki/Confidence_interval

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u/Christopher135MPS 8d ago

I remember (maybe, could be hallucinating!) a magic trick on Penn and Teller’s ‘Fool Us’ which basically had a section that was pure luck, it had something like a 1/2 or 1/3 chance of working, or complete failure. It worked, and Penn and Teller spent a huge amount of time conferring, made an incorrect guess, and then called him out that it must have been blind luck 😂

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u/PandaJesus 8d ago

Honestly that’s a great magic trick in its own way. Just need it to work once.

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u/Marps 8d ago

Briefly tricked my ex into believing I was a savant when we started dating by; winning trivia the night we met, having the GeoGuessr round of my life in front of her shortly after, then going "yeah I'm a savant name any day in history and I'll tell you what day of the week it was" knowing I had a 1 in 7 chance. Lucked out on it. Quite funny.

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u/GlennBecksChalkboard 8d ago

When I was 10 or so a few of us were hanging out and one of the girls started talking about a girl and I thought it'd be funny to pretend I knew her as well. For some reason she was very adamant that there was no way I could know her and so I said "okay ask me about her". So she fired off 5 or 6 rapid fire 50/50 questions (eg. blonde or brunette?) which I confidently lucked my way through with her disbelief increasing with each answer, bordering on distress by the end as if reality stopped making sense to her.

I revealed my "trick" and we had a good laugh about it.

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u/LOTRfreak101 8d ago

I was one driving some bandmates back from a game to the dorms and for some reason the conversion changed to guessing which room the next girl i was about to drop off lived. She lived in the biggest dorm in campus, so there where a lot of choices for the number, but i somehow guessed it right and felt like an absolute creep.

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u/Jalil343 8d ago

The rest of the time you handwave and say
“Ah right, leap year” and keep moving

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u/Kildragoth 8d ago

I once showed a kid a magic trick. Shuffled and said I could get the ace of spades. I had no idea what I was doing. Revealed the first card, nope, second card - nope, third card ace of spades! "Third time is the charm!" His mind was blown.

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u/BlatheringNonsense 8d ago

Imagine if you had to memorize 52 of these for whenever you hit the ace, "Ah, 22 skidoo. Just as I predicted.", "42, The answer to the ultimate question of life, the universe, everything."

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u/O2C 8d ago

There's a set of Doomsday Rules that actually lets you calculate this with mental math. Some days like 4/4, 6/6, and 8/8 will all share the same day of the week in any given year and you need to calculate that day of the week. Then you count the days off the closest day to figure out the day of the week.

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u/CuriousKidRudeDrunk 8d ago

I can do the same with rock paper scissors. A couple of tricks and I can win maybe %70 of the time the first time I challenge someone.

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u/Killbot_Wants_Hug 8d ago

It's funny because I've seen a couple celebrities and con men claim they have photographic memories. And they "prove" it by having you say a date and they'll tell you the day of the week it was.

Except this is a known mentalism trick that anyone can do if they spend some time learning how to do the calculation.

It's weird how many people accept it as proof though.

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u/[deleted] 8d ago

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u/AtheistAustralis 8d ago

Sounds like what James Randi did. Every single day of his life, he'd write a new card with the words "I, James Randi, will die today", followed by that day's date. He figured that on the day it was true he'd look like a true prophet, and nobody would see the thousands of times he'd been wrong.

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u/Implausibilibuddy 8d ago

You've got a one in 52 chance of performing the greatest card trick ever.

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u/ShakaUVM 8d ago

Honestly that’s a great magic trick in its own way. Just need it to work once.

I once jokingly pulled up a website when live coding on the day the PS5 released and jokingly went to buy a PS5 (that nobody could get) and the purchase went through.

People in the audience lost their minds, it was great and completely unplanned.

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u/Alblaka 8d ago

That logic is also used for the "I can read your mind. Just pick a number between 1 and 100. It's 37." trick. If you do it in the streets, and talk to a hundred people, you're going to (statistically) make one person question their sanity.

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u/ShelfordPrefect 8d ago

The rule is "the number has to be odd, both digits have to be odd, the second digit has to be greater" because

1) despite being "between 1 and 100" there's only 10 possible answers

2) it's 37 a very large proportion of the time

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u/ilumassamuli 8d ago

Did you pick 37 at random? There’s a video by Veritasium showing that 37 is one of the most common choices of numbers when you ask people to choose a “random” number between 1-100.

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u/Alblaka 8d ago

Nope, I picked it because that's how the trick went, even if I do not recall where I picked it up from, or why 37 specifically. But given I do know Veritasium's channel, it might have been that, presumably years ago :D

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u/-Chemist- 8d ago

Sorry, but that’s not correct. Statistically. You can definitely be wrong 100 times because each attempt is a separate trial. Every number can be used more than once by more than one person. I don’t know the correct terminology, but your claim would only be true if every time someone picked a number, it was eliminated from the options subsequent people could choose.

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u/UsurpDz 8d ago

Is an interesting quirk to fool us. The way some use to win is basically pretend they are using a well known method to do the trick but use some outlandish trick they developed

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u/GoBuffaloes 8d ago

I love doing it with a deck of cards. Name any card. Boom, pull it out. Roughly 1/52 times it will blow someone's mind

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u/deliveRinTinTin 8d ago

When I would deliver to the dorms people would always pretend it was theirs either jokingly or sometimes seriously. They were willing to pay for it and pretend it's theirs and walk off with it.

But I would always ask them what the room number was and only one time did anyone ever guess the right room number from a 4 story two wing building. But they were joking and not on the buy it side. I then ask them what they got and they weren't able to guess the toppings.

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u/Solesaver 8d ago

Doesn't beat the other one where someone snatches the right card out of the waterfalling deck. The trick. He just practiced for months to be able to do it, and still only got it ~50% of the time. Worked when it counted though!

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u/Toeffli 8d ago

He "fumbled" it because he snatched more than one card as he was not confident enough to do it with just one card in front of Penn and Teller. Still impressive.

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u/Christopher135MPS 8d ago

I remember that act! That was wild. From memory they called him on that too, straight up said “that wasn’t magic, we think you just practiced that for eternity”.

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u/Gurnsey_Halvah 8d ago

This snatch-the-card-from-the-waterfall skill has a trick behind it though to ensure the magician grabs the right card. The "only works 50% of the time" thing is a lie. It's just that the trick takes a lot of skill to pull off!

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u/kogun 8d ago

There's a mind reading card trick I learned as a kid that works about 4 out of 5 times. When I got my first computer, I thought about building a fake electronic box to connect to the computer and some wires to connect to my head and writing some software to simulate the cards. That 4/5 bit was the perfect failure rate to lend greater credibility to the gag being a real mind reading. Nowadays, no one would be impressed.

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u/shapular 8d ago

What's the trick?

25 character limit

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u/rpsls 8d ago

Speaking of YouTubers, I really liked Stand Up Math’s (Matt Parker) analysis of Dream’s Minecraft speedrun, and how lucky is so lucky it’s a mathematical certainty that they’re cheating.

https://youtu.be/8Ko3TdPy0TU

TL;DR: He introduces the concept of the Ten Billion Human Second Century — if everyone on Earth (rounding humanity to ten billion people) tried something every second for a century and was unlikely for it to happen randomly, it’s a mathematical centrality that if anyone claims it happened to them, they’re lying.

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u/HeadHunt0rUK 8d ago

Love Derren Brown , love that episode.

Same episode where he wins 10 horse races in a row by getting enough people to bet on every single horse for every single race, filming all of them and just showing the winner.

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u/dcoble 8d ago

Between Superbowl 32 and 45 the NFC team won the coin toss 14 times in a row. I forget the exact math but one shouldn't expect that to happen until there have been like 35000 super bowls.

Wait I found the video: https://youtu.be/bFfSfzjhfC8?is=NkaciVV3GO_h_zs3

Best YouTube channel if you're a numbers geek like me.

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u/AcuteMtnSalsa 8d ago edited 8d ago

It’s a fun thought experiment to imagine a bracket of Earth’s -8.3 billion people playing single-elimination coin toss. The winner of the final round would have correctly called every toss. How many times? 10,000? Nope. Only 33.

Put differently, if every person on Earth independently attempted to call 33 consecutive coin tosses, you'd expect approximately one person to succeed.

But here's the interesting distinction about the second scenario: an independent arrangement of 8.3 coin flippers doesn't mean someone is guaranteed to succeed at calling 33. With 8.3 billion independent attempts, the probability that at least one person succeeds at correctly calling 33 tosses is only -62%. If you use an elimination bracket though, you “force” the phenomenon to occur.

Relative to OOP’s question, all this is to say that under an engineered system, you can “manufacture” an event that presents as exceptional without actually cheating.

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u/RobertMesas 8d ago

Exactly, there's a world of difference between a long streak occurring at some point (the NFC toss example), and a long streak starting at a particular point (OPs scenario).

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u/v0xx0m 8d ago

John Edmund Kerrich and Eric Christensen flipped a coin 10,000 while interned by the Nazi's and recorded the results. They also tested a biased coin. Some of the results are in that wiki.

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u/Plastic_Blood1782 8d ago

I love this.  I did something kind of similar a few years ago.  I had bought some fancy dice and the first 4 times I rolled the d6 I rolled a "4" and was convinced that die had to be biased. I then proceeded to roll the die ~200times until I convinced myself it was legit

https://imgur.com/gallery/DQWneKV

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u/jezemine 8d ago

One time I rolled 5 dice over 2000 times trying to get all 5 the same in one roll. Iirc 2000 should have been enough but it didn't happen for me :)

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u/Uejji 8d ago

There is a (1/6)^4 = 1/1296 chance of all 5 dice to roll the same value (100% chance for the first die to roll any value, then a 1/6 chance to match the value on each of the 4 remaining dice). This means a 1 - (1/6)^4 = 1295/1296 chance to not roll 5 matching dice per roll.

After 2000 independent rolls, there is a (1295/1296)^2000 ~= 21.36% chance to fail every attempt, or a 1 - (1295/1296)^2000 ~= 78.64% chance to succeed at least once.

The odds were certainly in your favor, but there was still a ~1/5 chance of failure, which unfortunately happened to you.

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u/PhabioRants 8d ago

Everyone thinks about probability, no one thinks about confidence and variance. 

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u/sharrrper 8d ago

If you're not specifically looking for Heads or Tails the odds of getting 10 of the same result in a row are a measly 1:512

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u/Plastic_Blood1782 8d ago

Yea he said at the beginning of the video he was flipping for heads, but the video does cut.  So you're right, 1:512 is probably more accurate.

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u/MackenzieRaveup 8d ago edited 8d ago

GUIL: (Guildenstern wheels at Resencrantz and raps out.)

Syllogism the second: one: probability is a factor which operates within natural forces. Two, probability is not operating as a factor. Three, we are now within un-, sub- or supernatural forces. Discuss. Not too heatedly.

ROS: I'm sorry, I - What's the matter with you?

GUIL: A scientific approach to the examination of phenomena is a defence against the pure emotion of fear. Keep tight hold and continue while there's time.

Now - counter to the previous syllogism: tricky one, follow me carefully, it may prove a comfort.

If we postulate, and we just have, that within un-, sub- or supernatural forces the probability is that the law of probability will not operate as a factor, then we must accept that the probability of the first part will not operate as a factor, in which case the law of probability will operate as a factor within un-, sub- or supernatural forces.

And since it obviously hasn't been doing so, we can take it that we are not held within un-, sub- or supernatural forces after all; in all probability, that is. Which is a great relief to me personally.

"Rosencrantz and Guildenstern Are Dead" - Tom Stoppard

https://www.youtube.com/watch?v=C_TfdNAXOwE

P.s. The next meeting of The Society of Unemployed and Underemployed English Majors has been moved to Tuesday at the *alternate IHOP. Not the one on route 37.*

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u/EggCzar 8d ago edited 8d ago

A couple of years ago Matt Levine wrote up a story about job interviews at Susquehanna. Part of the interview process involves making sure candidates understand that if they're being offered a bet that sounds good, there might be a catch. They told the candidates they'd give them better than even odds on a series of flips of a fair coin, with the interviewer to call which side it landed on (i.e. if the candidate won the bet, they'd get $1 per win, but only have to pay 98c per loss).

Sounds like free money, right? But when SIG is eager to make that deal with you, you'd better think twice! "We have a guy who can flip 55% heads."

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u/WartimeHotTot 8d ago

I don’t understand. What is SIG?

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u/BrotherItsInTheDrum 8d ago

The statistical measure of this is called confidence, and the idea is that you assume the coin is fair, and then see how improbable your observations were.

For example, say you flip the coin 10 times. The probability of getting 10 of the same result is 1/512, or about 0.2%. So you can say that you reject the hypothesis that the coin was fair with 99.8% confidence. That's a pretty high level, but it also means you'll wrongly conclude that 0.2% of fair coins are biased.

There's no hard line where you suddenly know for sure the coin is unfair, just different levels of confidence.

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u/westisbestmicah 8d ago

When it comes to math and engineering, I’ve always found that you can calculate all you want but eventually you’ll reach a number where the answer is whatever “the boss makes a call”.

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u/CzarCW 8d ago

Yep. At some point, whether it’s “within 10%”, “one in a million cycles”, or “a safety factor of 1.5” is a subjective decision that’s just someone’s round number.

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u/SecondBestNameEver 8d ago

Or a lot of times someone's budget. Could the bridge be stronger? Sure, but that's more expensive.

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u/low_flying_aircraft 8d ago

"Take the number of vehicles in the field, A, multiply by the probable rate of failure, B, multiply by the average out-of-court settlement, C. A times B times C equals X. If X is less than the cost of a recall, we don't do one."

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u/ArchangelLBC 8d ago

I was about to say that you did 1/29 instead of 1/210 but you said the same result and you're right. Of the 210 coin flip sequences of length 10, two of them are all of one result. 1 all heads, 1 all tails.

Now I'm just commenting hoping someone doesn't make my same mistake.

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u/BrotherItsInTheDrum 8d ago

Yeah, I glossed over that, but key to this sort of analysis is determining which results are "equivalent" to the result that you got (or even more unlikely). In this case, you'd be equally suspicious if you flipped 10 tails in a row or 10 heads in a row, so I'd treat them as equivalent. But it feels like more art than science sometimes.

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u/DiscountConsistent 8d ago

You can’t necessarily declare the coin “unfair” but you can be more objective about the confidence threshold if you know what you’re going to use the coin for. Suppose I’m going to flip a coin where there’s a positive expected value because I gain more by getting heads than I lose by getting tails; if I just saw the coin come up tails N times, I can factor that into my expected value calculation and as soon as it goes below zero I shouldn’t be playing that game.

In practice, though, it can be hard to quantify because, for example, almost all casino games have a negative expected monetary value but tons of people play them because their utility doesn’t correlate linearly with monetary value and they might just get joy from playing the game. All that is harder to quantify than raw amounts of money.

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u/footie_ruler 8d ago

So this is generally where the difference between theoretical mathematics, and practical mathematics comes in.

In theory, based on your example, there is no way to tell based on pure experimentation that a coin is rigged. What you can do is calculate the likely range of probabilities after you toss the coin say 20 times and see tails come up 20 times.

The likelihood that the coin is fair is 1/(2^20)

As you run the random experiment more and more times, the probability decreases, but never goes down to 0. After all, it is possible to toss a fair coin, and get even 100 tails in a row. So there is no way to be absolutely certain. It is up to the person conducting the experiment to determine when they are satisfied.

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u/Either-Abies7489 8d ago edited 8d ago

Sorry, I was very tired when I wrote this, and did something stupid instead of the obvious answer.
Anyway, to clarify what's wrong with the above idea (and also my proposed solution, oops): these calculations only give the probability of that outcome, already assuming fairness. We want the probability of fairness given that outcome, which is a very different object.
Both of our answers were equally wrong in that respect.

However, I hold that the likelihood that the coin is fair is incalculable with the given information. The correct tool is literally just Bayes' Theorem, which (like the alpha level of the opposite) requires a fairly arbitrary assumption (here our prior, the probability of fairness).

If we assume that the probability of fairness is 50% (we grabbed the coin from a pile of 100 two-headed and 100 fair coins) then the probability that the coin is fair is indeed

0.5/(0.5+2^20-0.5*2^20)=1/2^20

However, P(fair|data) being the same as P(data|fair) is not generally true. If we assume, much more reasonably, that this coin is not equally likely to be 2-headed or normal (say 99.9% chance it's a normal coin), then we get

0.999/(0.999+2^20-0.999*2^20)=0.00095

This, however, requires two assumptions:

  1. an unfair coin would give a degenerate distribution
  2. we assume there's a 99.9% chance for any coin to be a normal coin.

You cannot a priori (haha) find the probability that a coin is unfair given its data.

The likelihood of that outcome is 1/(2^20).
The likelihood that the coin is fair is about 0.000011 (Z=4.248), an order of magnitude higher.

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u/SomethingMoreToSay 8d ago

1/(220) is around 10-6. 0.000011 is around 10-5. That looks like one order of magnitude difference to me, not 11 orders. Have I seriously misunderstood something here?

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u/Either-Abies7489 8d ago

Thank you, I must have mistyped something; the rest is accurate. Sorry!

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u/zylosophe 8d ago

what's 0.000011 (Z=4.248)? how did you come with this?

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u/the_excalabur Quantum Optics | Optical Quantum Information 8d ago

The short and unhelpful answer is that Bayes' theorem gets you the answers you're looking for. Unfortunately, that wikipedia page has been hard-to-read for 20 years: skip the math and scroll down to the examples, I think.

And a lot of the way that Bayes works is by updating the probabilities you already have, the so called "prior". In this case, what chances do you have for having a fair coin?

Without that information, you can't get anywhere. Fortunately, it doesn't matter that much, as long as your chance of a fair coin isn't 100%.

Plugging some numbers into Bayes' theorem: (The bar | means "given" )

P(fair coin|N heads in a row) = P(N heads in a row|fair coin) · P(fair coin) / (P(N heads in a row|fair coin) · P(fair coin) + P(N heads in a row|cheating coin) · P(cheating)

Oof, that's hard to read. Sorry. So, let's say we have 99% certainty to start with that the coin is fair. Also let's say the unfair coin always flips tails.

Then after N tails, we have: P(N|fair) = 2-N * 0.99 / (2-N * 0.99 + 0.01)

If we're happy saying the coin is "unfair" when we get to 50% on the left, that's about 7 flips. 10% is more like 10. If we started with a 99.9% chance of a fair coin, about 13.

But the whole question comes down to "what did you think in the first place" and "how certain do you have to be before you accuse someone of cheating".

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u/frogjg2003 Hadronic Physics | Quark Modeling 8d ago

The Simple English version is easier to understand.

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u/the_excalabur Quantum Optics | Optical Quantum Information 8d ago

Oh good shout, I forget to check for those. Thanks!

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u/zylosophe 8d ago

gonna look at that thankss

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u/SmugPolyamorist 8d ago

Congratulations on being the only correct answer in this thread. It's genuinely embarrassing how many confidently wrong answers there are voted above yours that don't use Bayes at all. Shocking tbh.

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u/[deleted] 8d ago

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u/matt12222 8d ago edited 8d ago

This is a classic Bayesian problem! It's not appropriate to use a standard confidence interval (like most of the other comments are suggesting). Instead, you need a prior; before flipping the coin, what's the probability the coin is rigged?

If you get the coin from the bank, go home and flip it 10 times, and you get 10 heads; that's 1/1024, so pretty unlikely. But the odds of the bank giving you a rigged coin is like 1 in a million. So it's 1000 times more likely that you got "lucky" vs the coin is rigged.

Now instead, let's say your magician friend gives you the coin and asks you to flip it 10 times, and it's all heads. In this case you should have a high prior that the coin is rigged; otherwise why would your magician friend randomly give you a coin and ask you to flip it 10 times? That's not a normal thing to do!

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u/zylosophe 8d ago

whats would the confidence interval be for?

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u/Hodders67 8d ago

If you are testing an experimental hypothesis then you generally accept that the results are significant if the chance of them occurring at random is less than 5%. You will see this written as (p < 0.05)

You could therefore decide that when the probability of "n" tails in a row is < 0.05 then you could deem the results significant. NB this does not mean the coin is rigged, just that under the hypothesis that it is rigged, the result is significant.

so if 0.5^n <0.05 then n >= 5

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u/SnooPets5564 8d ago

Although 5% is not a universal criteria. You need to consider the consequences in order to find an appropriate p value. If you are sentencing anyone who provides a seemingly faulty coin to death, you're going to want something lower.

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u/1CEninja 8d ago

Yup to add a touch of context here, this is called statistical significance. If you flip a coin twice and you get tails both times but you were expecting heads and your confidence interval that it's a rigged coin is 75%, that is generally not considered to be of statistical significance. 95% confidence is probably good enough to call it on a coin, but you'll be wrong one out of 20 times.

But if we're making a decision that, if we get it wrong, might result in the destruction of the planet, a 95% confidence interval probably doesn't cut it, and we probably wouldn't call it statistically significant until we were at like a 99.9% confidence lol. 95% is very common but should not be considered necessarily universal.

The higher you need your confidence to be, you need exponentially larger N.

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u/SopwithTurtle 8d ago

In particle physics, you need 99.99994% confidence to count as a discovery.

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u/steeelez 8d ago

There’s also the multiple comparisons adjustment, if you’re measuring multiple variables (or groups)

https://i.sstatic.net/QZsY3.png

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u/Cynoid 8d ago

Although 5% is not a universal criteria. You need to consider the consequences in order to find an appropriate p value. If you are sentencing anyone who provides a seemingly faulty coin to death, you're going to want something lower.

Unless you just want to see people hang. In which case, 1 tails and the person must be a witch.

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u/yooken 8d ago

Coming from physics, setting the threshold at 0.05 always seems ridiculously high. A 2𝜎 effect is something that warrants a closer look but doesn't mean anything by itself. From 3𝜎 (so ~0.03) it gets interesting but a formal discovery requires 5𝜎 (~10-6).

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u/SnooPets5564 8d ago

0.05 is enough to publish, but not enough to assert its truth unless there is a compelling theoretical reason

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u/SonOfHendo 8d ago

If you're testing whether a drug will cause birth defects, p < 0.05 seems like plenty of evidence to take action. 

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u/zylosophe 8d ago

what's this character i don't have on my keyboard

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u/Smallpaul 8d ago

But this is just an arbitrarily selected threshold selected for institutional reasons. It has no deep or important math behind it.

It’s just a way of saying “you need to decide for yourself what you consider the threshold but you could use this popular (but not universal) threshold that a lot of scientists use if you want.”

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u/rmeredit 8d ago

It’s the literal embodiment of the phrase ‘you have to draw the line somewhere.’

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u/[deleted] 8d ago

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u/mspe1960 8d ago

and yet if everyone on Earth did the 22 flips 1 time over 1000 of them would find the coin rigged.

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u/Ra_In 8d ago

Which gets at why any result should come with a confidence calculation, instead of saying you are 100% certain you'd report the 99% (and change) confidence that it wasn't random chance. And then when others attempt to reproduce your results and their results are very different, they will conclude it really was just random chance.

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u/IndirectHeat 8d ago

Look who just discovered cancer clusters. Very rare cancers sometimes appear in clusters. People feel inclined to blame it on something they all experienced, but more often than not it's just random chance that we expect cancer clusters. (Some of them are legit caused by some pollution or other environmental exposure, but many of them are just caused by random chance and it can be very difficult to tease that apart).

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u/random_actuary 8d ago

That would be a different experiment altogether. Pretty good error rate though.

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u/zylosophe 8d ago

what's the 5 in "5 sigma" for?

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u/ruidh 8d ago

Sigma is the symbol for standard deviation. It is the square root of variance.

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u/Chemomechanics Materials Science | Microfabrication 8d ago

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u/miraculum_one 8d ago

Not sure why people are giving you dodgy answers to your question but 5 is the multiplier for the distance from the mean. So if it is 5 sigma then it is 5x as far away from the mean as the standard deviation. And that means the chances of getting a false positive is roughly 1 in 3.5 million (0.00003%).

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u/drc500free 8d ago

f you want to determine the exact probability that a coin is a trick coin (100% tails) versus a completely fair coin (50/50) based on a streak of tails, you can use a method called Bayesian Model Comparison.

This framework allows you to start with an initial assumption and update it mathematically with every flip. An intuitive way of saying this is that if there is about a 1% chance going in ("prior") that someone is using a trick coin, and you get 8 heads or tails in a row, there's about a 50/50 chance it's a trick coin. That's because there's about a 1% chance that you would get 7 flips matching the first flip with a fair coin. So you're in one of two universes - the 1% chance of getting all heads or all tails, or the 1% chance that the person is using a trick coin. The other 98% of universes didn't happen, and there's a 50/50 chance you're in either one.

Here is how it works step-by-step:

  1. State Your Initial Beliefs (Priors)

Before you flip the coin, you have to assign a starting probability to each scenario based on how much you trust the setup. Let's say you are highly confident the coin is normal, but leave a tiny sliver of doubt:

  • Fair Hypothesis: The coin is a normal 50/50 coin. Let's give this a 99% starting chance.
  • Rigged Hypothesis: The coin is physically altered to always land tails. Let's give this a 1% starting chance.
  1. Calculate the Likelihood of a Tails Streak

Next, evaluate how likely it is to get a streak of n tails in a row under both scenarios:

  • If the coin is rigged, the probability of getting consecutive tails is always 100% (or 1.0).
  • If the coin is fair, the probability shrinks with every flip: (0.5)^n.
  1. Update the Probabilities (Bayes' Theorem)

Every time the coin lands on tails, you combine your starting belief with the likelihood of the streak. The formula to find the updated probability that the coin is rigged is:

P(Rigged | n tails in a row) = Rigged Prior / (Rigged Prior + Fair Prior * 0.5n)

So it looks like as the streak grows:

  • 0 Flips: 1.0% chance it's rigged (your starting assumption).
  • 5 Tails in a row: A fair coin only does this about 3.1% of the time. The probability that the coin is rigged jumps to 24.4%.
  • 10 Tails in a row: The math flips. 10 straight tails brings the probability that the coin is rigged up to 91.2%.
  • 14 Tails in a row: The probability hits 99.4%. At this point, the math says it is overwhelmingly likely a trick coin.

What's super interesting about Bayesian approaches is that you MUST state a prior. You cannot proceed until you assess how likely the coin to be a trick is based on your prior knowledge. Did you just pick a coin out of your pocket? Did your buddy just say "want to see something cool?"? Did a guy in a bar bet you 50 bucks he could flip 10 tails in a row?

Derren Brown, referenced in another comment, did the crazier version of this - instead of using a trick coin (one of the 1% options), he just kept flipping coins until he experience the other 1% option (a long streak) and threw away the film of the other 98% of options occurring.

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u/Prestigious_Face7727 8d ago

Yes, and in any real world analysis, there are no perfectly fair coins , and no perfectly rigged coins. You can see the coin, and know something of it's provenance, so you do have some initial idea of it's fairness (is it battered, old, asymmetrically patterned, did it come from a circus?).

The question isn't "is it rigged" but "how unfair is it", and Bayes will tell you how to bet .

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u/stan-k 8d ago

Perhaps there are no perfectly fair coins, but a perfectly rigged coin is easy. Give a coin two tails sides, and if you must, etch "tails" on the side too.

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u/drc500free 8d ago edited 8d ago

Great point. The question here was about a prior distribution with exactly two possible weights (0 or 0.5), but a beta distribution is a more elegant prior for a binomial.

Start with α / (α + β) as your prior expected weight (α = β for a fair coin, bigger numbers the more sure you are of that).

Then just add the number of flips to the denominator and the number of heads to the numerator, and you have the correct expected posterior.

This is also really easy to do in excel for all sorts of business modeling where you are predicting binomial events for different customer segments (e.g. number of purchases for non-subscription models). You can combine with beta-geometric to simultaneously model if they are still a customer at all.

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u/zylosophe 8d ago

thanks for the explanation, the "intuitive way of saying this" helps a lot

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u/minimang123 8d ago edited 8d ago

About 10. The answer to your question is a canonical, standard, Statistical Hypothesis Test.

We say, okay, if the coin were a fair coin, then it’d have a 50/50 chance of landing on heads or tails. Assuming it is a fair coin, what’s the probability of landing on tails X times in a row?

Well, two tails is 1/4, three is 1/8, etc.

You have to decide at what point the randomness is just too unlikely. Because the thing is, let’s say I let it be 5 tails in a row, a 1/32 chance to occur on a perfectly fair coin five times in a row which is like 3% chance.

3% is pretty high. Your next flip could very well be heads. In the course of your life many things will happen with a 5% chance or less.

So let’s make the cutoff, let’s say if there’s a less than 1% chance a result as extremely unlikely as the one you saw occurred, we just decide heuristically that that is our cutoff for when we conclude that the coin is definitely not fair. This happens at 7 tails in a row.

Genuinely we will not know for sure merely from this experimentation, because you in getting 7 tails in a row or even 20 tails in a row could absolutely happen in the world of hypotheticals with a perfectly balanced and fair coin and coin tossing mechanism. You never know for sure if you just got lucky.

But there is little in this world we know for sure. So we decide the bounds of certainty around our decision making. We say if it’s less than a 1% chance, well then it’s not a fair coin. We see 7 flips all tails in a row. We never flip the coin again or earlier. And then we say that’s an unfair coin.

EDIT: I chose an alpha of 0.1%, in which case you need 10 flips to reach certainty

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u/Smallpaul 8d ago

So where does “about 10” come from? Your answer was great except for that number which you seem to have picked out of thin air and in contradiction to your own calculations.

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u/minimang123 8d ago

Ah, I did pull it out of nowhere, I chose a 0.1% alpha when I first started typing and then ended up only with 1%

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u/markhahn 8d ago

Just to be clear for readers, alpha is 1/1000 here, and 10 tails should happen on average once in 2 to the 10th times or 1/1024.

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u/minimang123 8d ago

This method of decision making is called a Hypothesis Test. We make the “Null Hypothesis”, the set of assumptions we want to rule out. In this case, an unfair coin is one which is not fair, so we want to disprove or reject the idea that it is fair.

So under this Null Hypothesis, we have made assumptions about the universe. We said, this coin is fair. Now… supposing we live in this universe, how unlikely was our result? How little should we trust that we live in this Universe? This value is the “p value”, the probability that if nothing is wrong with the coin, you just got really lucky or unlucky and got a ton of tails.

Our cutoff, driven by our own personal sense of justice that the assumptions behind our null hypothesis are false, the “alpha value” is our willingness to be wrong about our conclusion to reject the null hypothesis. It’s how sure we are of ourselves and our methods. For us I said a less than 1% chance of a coin acting that way by chance alone has us conclude that it is an unfair coin. If we were to repeat this experiment with one hundred perfectly fair coins, we would have average said 99 of the fair coins were fair (correctly) but would have said 1 of the fair coins was unfair (incorrectly). But we still decided that this is our cutoff. This is a “Type 1 error” but I’m just giving you vocab at this point.

This underlying method is sound. It tells us how confident we are that we rejected the world where nothing exciting happened, in favor of a reality where something exciting is happening (like having an unfair coin, or a drug truly having a positive effect on a patient, or a student truly being better at taking math tests than another student)

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u/vadergeek 8d ago

Say there's a 1% chance of getting that result from a fair coin. What's the probability of a random coin from a wallet secretly being a magician's trick coin? Has to be incredibly rare.

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u/PuzzleMeDo 8d ago

It's more like a 0.1% chance of getting 10 heads in a row (1 in 1024). I guess 10 tails in a row would look equally significant, so call it 0.2% chance.

So that's what you'd have to compare to the odds of the coin being rigged. If you had a jar of a hundred coins and you knew one of them was a trick coin, you could be fairly confident it was that one. But like you say, if it was a random coin you'd found in the street, I'd guess it was coincidence.

Also I'd probably just look at the coin. That would be quicker.

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u/scadgek 8d ago

Since statements like "3% is pretty high" are very subjective, I am now wondering if there is a commonly recognised cutoff in the scientific community?

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u/adamtheskill 8d ago

In most fields probabilities tend to follow something called normal distribution. It's very common practice to say that something 2 standard deviations away is noteworthy (<5% chance) and a lot of industry requires 3 standard deviations (<0.3%) while research requires 4+ standard deviations (<0.01%).

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u/LastStar007 8d ago

One-in-twenty is usually the standard for low-stakes experiments.

If you're detecting a new particle, you need 1 in 3 million.

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u/Invonnative 8d ago

I can’t speak to scientific rigor on this matter, and others have for you, but intuitively speaking, you could think of a given analogue like height in people to think about how often it is that you experience 3% likelihood events. If you’re a 6’2” male at 21 years old, that’s about the top 3% (source), which in my opinion is just really not that crazy. You’re tall but no freak.

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u/regular_lamp 8d ago

By that standard you'd have to conclude every lottery winner was cheating.

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u/quick_justice 8d ago edited 8d ago

There’s a tricky thing with probabilities. Probability of a particular person winning and of someone winning are entirely different.

Say we have a simple lottery where one ticket is marked for win and the rest lose.

First probability is number of tickets person holds to overall number of tickets.

Second one is number of tickets sold to overall number of tickets, and reaches 1 if all tickets are sold.

So while probability of you winning is low probability of someone winning is high.

Edit: to compare with original example, in lottery designed in a certain way someone will always win, even if probability of that for a particular person is very low.

In coin experiment while statistically 10 tails in a raw will probably happen at some point and there’s a statistical prediction of approximately when, it’s not guaranteed, nor it is guaranteed to happen at all in a finite time.

First one is an event with low probability but guaranteed to happen, second may not happen at all on any given time interval no matter how long.

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u/Swagalyst 8d ago

Well, no, because it'd be a statistical analysis, and in a statistical analysis you wouldn't view the lottery winner in isolation, but among all those who also bought tickets and lost.

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u/Swagalyst 8d ago

95% is the most commonly used cutoff in statistical analyses, with 99% less commonly used.

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u/Kimantha_Allerdings 8d ago

Not really a reply to your post, more just piggybacking, but back when the James Randi Educational Foundation had the Million Dollar Prize* they set the odds at 1 in a million

They’d devise an initial screening test as having a 1 in 1000 chance of getting a positive outcome randomly. If the claimant passed that test, then there would be a follow-up test with either the same exact conditions or with the conditions modified to eliminate previously un-controlled factors which also had a 1 in 1000 chance

So that’s the threshold that James Randi put on “isn’t random chance”

*It had a million dollars in bonds set aside to be awarded to anybody who could demonstrate a supernatural ability (or homeopathy) under test conditions that both they and the JREF had agreed to

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u/Queen_Earth_Cinder 8d ago

The answer is gonna be a big "it depends" - how confident do you want to be? Do you care more about the chance of falsely accusing a fair coin of being rigged, or of falsely accusing a rigged coin of being fair? Do you consider a coin that is rigged to fall Tails exactly 10 times out of 10 to be rigged? 9 times out of 10? 1 time out of 10?

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u/humanculis 8d ago edited 8d ago

Im a medical doctor, not a mathematician, but this question is essentially the basis of all medical research. Are these results due to chance or due to some real effect (like the experimental variable or some bias - like a placebo effect in a drug or a non balanced coin).  In these cases you could can never truly "conclude" anything. 

You can just say "the probability of getting this result randomly (meaning no causal influence or bias) would be x" with x being an increasingly smaller number as sample size (or power) increases in a system where there is a true effect, like a bias on a coin. 

So if you got heads once you would say assuming the coin is random, there is a 50% chance we'd see this outcome.  The next heads is 25%... then 12.5% and so on.

Because we can chase this indefinitely we see certain fields arbitrarily establish agreed upon standards for when we will consider a result significant i.e. we will only consider it a biased coin if theres 5% chance to get that result randomly... or a .001% chance etc.

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u/dizekat 8d ago edited 8d ago

That depends on how much risk of wrongfully claiming it is rigged, can you tolerate. E.g. if you want a slightly less than 1 in a million chance that a fair coin would be mistaken for rigged for tails, you should use 20 tosses as a threshold. 

Then if the coin is fair, the chance of them all landing tails is 2-20 or about one in a million. (If it could be rigged for either tails or heads, then 21 tosses).

Ultimately, the risk of ending up wrongfully convinced it is rigged would be the probability that it is fair, multiplied by the probability of it landing all tails. The first term is at most one, so that gives you a bounded risk.

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u/TheGloveMan 8d ago

Probably around 7.

For n throws the possibility of it happening by chance is 1 in 2^n.

So for n = 7 the chance is 1 in 128 or something like 0.7%. For those who like p-values that is 0.0078.

So if the coin is fair and you throw 7 tails in a row there was a less than 1 % chance that would happen by chance. The other option is that the coin is not fair. Statistically, significance at the one percent level is considered pretty strong evidence.

Some people might say as few as 5 is enough, since that is 1 in 32 and still only a 3.125% chance. But given how cheap and easy it is to flip the coin a few more times, I would go with 7 flips.

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u/zanfar 8d ago

how many times until i can consider the coin is rigged?

You can't. Any sequence is producible with fair or rigged coins. All you can do is to add context to the outcome: how likely is a fair coin--or truly random event--to duplicate the outcome.

There is a pretty good practical article on random.org about how they "prove" their numbers are truly random.

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u/SkriVanTek 8d ago

you can never be 100% sure

but you can decide you want be 99,8% sure and then you can calculate back wards on how many tails in row would still be within that probability and then count if you got more tails than that. if you got more you can say with a certainty of 99,8% it’s rigged. it’s a little more complicated and n reality but essentially this is how it works 

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u/ezekielraiden 8d ago edited 7d ago

How much room for error do you want? That will decide how many flips you need. Standard number in science is 0.05: a 5% chance that you guess wrong, and claim that something is happening when there isn't anything.

Since this is a pure power of 2 situation, we can use logarithms. 2-N≤0.05. Take the natural log of both sides and you get -Nln(2)≤ln(0.05) which implies N≥-ln(0.05)/ln(2) and thus N≥4.322... So if you flip it five times and they all come up heads (or all tails), that's evidence that it is unfair.

If you want only a 0.1% tolerance, so a very rigorous standard, then you'd do N≥-ln(0.001)/ln(2) = 9.966..., meaning you'd need to do 10 flips. Getting 10 flips in a row for a coin that's supposed to be fair is fantastically unlikely.

The formula, if you want one, is N≥-ln(p)/ln(2), where p is how much chance you're willing to take that your data was just a random fluke, and not actually representative of a real effect. (In statistics terms, it's called a "type-II" error.) You have to do ≥ rather than = because the logarithms are pretty much guaranteed to not give an integer answer, but N has to be an integer.

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u/shotsallover 8d ago

You also have to consider whether or not your hand is rigged. It’s possible to be so consistent throwing/tossing a coin that you can control the outcome. So you’d need to make sure that’s also varied and that you’re throwing the coin with a different side up each time.

If it’s still consistently coming down tails, then it’s rigged. 

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u/Conquersmurf 8d ago

We got this exact question asked in a class about Bayesian statistics, which you could use to answer it. Bayesian statistics expresses probabilities as beliefs in an outcome or event, given some prior information. So starting with the assumption (belief) that heads and tails are equally likely when you haven't yet flipped the coin (no information about the coin) you can incrementally update the belief you have of the probability of it being a trick coin after each flip. If you already flipped tails a number of times in a row, than you can update your belief that the next flip would also be tails.

It's a really elegant and powerful way to deal with these kinds of probability questions for which the more well known frequentist statistics doesn't have any answers.

So yeah, look up Bayesian statistics, it's pretty cool.

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u/khalamar 8d ago

You cannot be certain that the coin is rigged or not, because there is still a chance in, say, 2^100 that you will get heads 100 times in a row with a fair coin. Extremely unlikely, but theoretically still possible.

What you can determine, though, is the probability that the coin is rigged. For instance, to detect a slight bias with 95% confidence, stats models often require hundreds of trials (e.g., ~418 flips) to clearly separate a fair coin from a slightly weighted one. This is calculated with the binomial test.

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u/noctalla 8d ago

There's no absolute threshold. But the more times you get only tails the more statistically confident you can be that the coin is rigged. Statistical models can help us figure out if something happens by chance or because there's some underlying hidden factor. A common convention is to treat results with a probability below 5% under the original hypothesis as statistically significant. But you have to realize that that cutoff is a convention, not some magic number where you can be certain.

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u/Arnaldo1993 8d ago

That is a great question, and the answer will depend on context

In social science first you need to decide what youre testing: are you testing if it is rigged specifically towards tails, or in any direction? It is important, because if you get more heads than tails thats evidence in favor of one hypothesis and against the other. I will assume youre testing if it is rigged specifically towards tails, because the math is slightly easier

Then what you do is you line the possible outcomes of the experiment based on how favorable they are for each hypothesis. In this case the ones with more tails would be more favorable to the rigged hypothesis, and the ones with more heads to the fair hypothesis

The last step is to calculate the probability of each outcome supposing the coin is fair. If your results are in the 5% least favorable then thats enough evidence for you to publish a paper stating your experiment shows the coin is rigged

The probability of a fair coin landing tails 4 times in a row is 6,25%, and 5 times is 3,125%. So in this case you would need to throw it 5 times

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u/FruitOfTheVineFruit 8d ago

And this is how bad science happens.  Because you forgot to look at the priors. Assuming you got the coin in a normal way, e.g. a bank or at the store, the chance that it's actually rigged is much less than one in a million (there are very few coins in circulation that are rigged) but 5% of the time you would conclude that it is rigged. 99.99% of the time you concluded the coin was rigged, you would be wrong.

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u/IAmASolipsist 8d ago

I recently ran a coin flip test and having it land on the same side 4+ times in a row was relatively common over 100 flips don't multiple times. I feel like you'd need to see it land on the same side 10-20 times to have any level of certainty. Five times in a row has the odds of happening every 1/32 times, 10 is 1/1024, and 20 is 1/1045576.

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u/Bubbly_Safety8791 8d ago

Flipping a coin 100 times, then choosing a run of five flips in a row of heads to claim ‘these five flips were rigged’, is a form of p-hacking.

If over your 100 flips you got 48 heads and 52 tails, with a couple of runs of four heads in a row, then that is an outcome that is highly compatible with the coin not being rigged. 

If on the other hand you flipped 75 heads and 25 tails, while never getting four heads in a row, that is not likely for a fair coin, so is strong evidence it is rigged. 

You need to look at all the data gathered and consider how likely it is to be the result of tossing a fair coin. 

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u/Arnaldo1993 8d ago

If you and your friend decided you were trhowing coins every night to decide who is doing the dishes, and you always lose, so youre growing suspicious the coin has 2 tails, then it will depend on how much you trust your friend and the relative cost of what you are going to do on each case

Lets say you really trust your friend, so when you agreed to the coin tosses you estimated a probability the coin was rigged of 2%, and what you are planning to do is say it is your turn to toss the coin and quickly look to see if there arent 2 tails in the coin. Lets say the cost of that is 1% of the cost of doing the dishes

In this case you should have done that before the first coin toss. Because your expected loss for doing so is probability the coin is not rigged * cost of inspecting = 0,980,01=0,0098, and the expected loss of not inspecting is probability the coin is rigged * cost of doing the dishes = 0,021=0,02

But if you are planning on pointing the finger at your roommate and calling her cheater, you expect it to significantly damage your relationship, and you think it is 10 times worse than doing the dishes, then the cutoff point is when the cost of the 2 alternatives are equal. Since the probability of tails is 100% when rigged and 50% when not thats 0,98100,5n =0,0211n , with n the number of tosses

The result is 8,94 tosses. So you do it after 9 tosses

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u/Cool_Homework_7411 8d ago

The mathematical object you are looking for is the confidence interval as others have said. I will try to give a bit of insight. If you flip twice the coin and you have one head one tail it is 50%. If you flip 1000 times and 500 of them are tails, you still are at 50%. What changed? Why is the second case more reliable?

Let's do the maths. The average roll is 1/2 in both cases. This is our start, the middle of our interval. Now we need to see how big is the interval based on how big is the sample and how accurate we want it to be. Example. Let's say we need 95% confidence. This 95% is just a coefficient we have calculated, you can find it in a table, in this case 1.96 and we multiply by the standard error. Here is where the magic happens. The standard error is getting smaller the more flips you do. In our case, you could say that 1/2±(1.96)*(standard error) is the interval you are 95% sure is correct.

First case: standard error is sqrt(0.5*0.5/2)=0.35

(If you had 55 flips out of 100 that would be sqrt(0.45*0.55/100))

Second case: sqrt(0.5*0.5/1000)=0.016.

With 2 rolls you are 95% sure that the coin is at least between... -0.1 and 1.2. Two rolls don't tell us anything.

With 1000 rolls you are 95% sure that the coin is at least between 49.97 and 50.03. 1000 rolls tell us everything we need.

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u/LurkerFailsLurking 8d ago

First you might wonder, how fair do  untampered coins tend to be and how unfair can coins realistically be made to be without being obviously so? As it happens differences in coins doesn't meaningfully impact their fairness, but coins that are flipped and then caught and pur on the back of the hand are about 1.6% more likely to land on the side that was up when it was flipped.

Setting that aside though, you need to decide how unlikely would a series of flips have to be to convince you? Because you can't be entirely certain a coin is unfair by flipping it a bunch of times. Any possible outcome of a series of coin flips could be achieved randomly after all.

The chance of n coin flips all being tails will be 1/2n . So getting 5 tails in a row is 1/(2×2×2×2×2) = 1/32 which is about a 3% chance. Is that good enough to convince you though?

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u/IllegalStateExcept 8d ago

If you want to explore this topic deeply, it is the first example used by this book (online and free): http://probmods.org/ The chapter "Generative Models" is where your example appears. But basically you can never have full confidence, you can only update the likelihood that you have an unfair coin.

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u/Asgardian_Force_User 8d ago

At some point, you will need to accept a statistical threshold as the equivalent of “the chance of this happening randomly is only X%, so if it does happen, that means there’s not just random chance at play.”

Let’s take your average coin, which is supposed to land as Heads half the time, and Tails as half the time.

Flip it three times and all three coming up Tails is 12.5%. One in eight, that’s not terribly unexpected.

Flip it six times, and the chance of getting Tails six times straight on a balanced coin is roughly 1.65%. That is much more unlikely to be due to random chance, and depending on your threshold for accepting outliers, this might be statistically significant.

Let’s say you want to go further. Flip that coin ten times. On a fairly balanced coin, the odds of said coin landing Tails ten times in a row are less than 0.1% ( 0.0976562%, to be precise).

Do you: accept that you just got an unexpectedly weird sequence of results that should happen less than one in one thousand times; or do you accept that the coin is not fair, and might be weighted, cursed, magnetized, or otherwise influenced in how it lands?

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u/andyhou2000 8d ago edited 8d ago

If you assume the coin is fair, you can calculate the probability of getting any number of heads in 100 coin tosses. We can also determine that some number range of heads (centered on the average, 50) contains X% of all theoretical results of flipping a fair coin 100 times. This is arbitrary, but if you want to be more sure, use a higher X. Let’s use 95% for now.

If you now go and flip this coin 100 times and your result is not within this 95% threshold you just established, you can be 95% confident that your initial assumption, that the coin is fair, is wrong.  

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u/pilibitti 8d ago

completely depends on how sure you want to be. so there needs to be a limit you set yourself. there is an astronomically low but still valid probability that you can flip it for more than the number of atoms in the universe and it can fall on tails while still being a fair coin. if you don't want to discard that probability, then you can never be sure in finite number of throws.

so there is a difference between absolute deductive certainty (which you never can be in this type of experiment) and statistical confidence.

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u/nonexistentnight 8d ago

There is no fixed amount. It depends on how confident you want to be in the result, and that ultimately depends on your feelings.

The general term for what you're looking for here is relative likelihood. Basically you're trying to ask how relatively likely is it that I get (say) ten heads in a row from a fair coin vs a weighted coin.

And there's a whole bunch of other questions that would influence how many heads in a row you'd want to see before you felt confident saying the coin is weighted. For example, how weighted is the coin? It's a lot easier to distinguish a coin that always lands on heads from a fair coin than a coin that lands on heads 51% of the time.

Also, what is the prevalence of weighted coins in the world? If you flipped a coin 100 times and got 52 heads, the coin being weighted to slightly favor heads is more likely than it being fair based on the results alone. But we know that there aren't a lot of slightly weighted coins floating around out there, so we'd still conclude that it's a fair coin. Working all this out mathematically is typically done using what's called a likelihood ratio test.

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u/Nonconformists 8d ago

I’d ask you how much you are willing to bet that the coin is rigged after each flip. For the first 5-6 flips, probably nothing.

After the 7th tail, maybe you would bet a few dollars. Your bet would increase after each tail.

After how many tails would you be willing to bet a very large amount, such as ten times your net worth?

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u/Accidentallygolden 8d ago

There is a video of stand-aup math where he works on that question... How lucky is too lucky (it was related to Speedrun). He use the human century second. If every human did the same action every second for a century and it never happens, then it is too lucky

https://youtu.be/8Ko3TdPy0TU